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3 years ago

What is the range of the graphed function?

Mathematics

1 answer:

Greeley [361]3 years ago

3 0

Answer:

what?

Step-by-step explanation:

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The square root of the quantity 4 x minus 3 end quantity equals 5.

zavuch27 [327]

Answer:

The statement is false.

Step-by-step explanation:

Given,

$\sqrt{4 \times - 3} = 5$

To Prove

Soln:

$\sqrt{4 \times - 3}$

= $2i \sqrt{3}$

=> $2i \sqrt{3} ≠5$

Hence, 2i√3 is not equal (≠) to 5.

3 0

1 year ago

Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu

Murljashka [212]

Answer:

The value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=30t-\frac{g_s}{2} t^2$

Velocity is defined as the rate of change of position. Therefore,

$v(t)=\frac{d}{dt}(s(t))$

So, the velocity function is

$v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st$

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

$v(t)=30-g_st=0\\\\g_s=\frac{30}{t}$

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).

So, the value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

5 0

3 years ago

Y< 3x + 6<br> Determine if (2,4) is a solution

kap26 [50]

Answer:

Yes

Step-by-step explanation:

4 < 3(2) + 6

4< 6+6

4 < 12

3 0

2 years ago

Read 2 more answers

Given: m =-2/3

Elenna [48]

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The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6 0

2 years ago

PLEASE HELP SHOW YOUR WORKING OUT Branliest

Ad libitum [116K]

Answer:

The equation of this line is therefore y = 2x + 3.

Step-by-step explanation:

this line passes thru the points (0, 3) and (3, 9). As we move from (0, 3) to (3, 9), x increases by 3 and y increases by 6. Thus, the slope of this line is

m = rise / run = 6/3, or m = 2. Inserting the known info (m = 2, x = 0, y = 3) into y = mx + b, we get: 3 = 2(0) + b, so we see that b = 3.

The equation of this line is therefore y = 2x + 3.

5 0

2 years ago