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Maksim231197 [3]
3 years ago
6

The ratio of the surface tension and density p of liquid 1 and 2 are 1:2 and 1:4 respectively. Equal amount of the two liquids i

s poured into two identical tubes. What will be the ratio of the rise in the liquid level in the two tubes?
Chemistry
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

The ratio of the rise in the liquid level in the two tubes will be 4:1.

Explanation:

Density is defined by the equation bellow:

p = m / V

m: mass

V: volume

p₁ = m₁/V₁

p₂ = m₂/V₂

p₁/p₂ = m₁/V₁ x V₂/m₂ = 1/4

equal amounts: m₁ = m₂

V₂/V₁ = 1/4

The ratio of the rise in the liquid level in the two tubes will be 4:1. This means that the liquid one has a volume 4 times bigger than the liquid 2.

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A gas evolved during the fermentation of alcohol had a volume of 19.4 L at 17 °C and 746 mmHg. How many moles of gas were collec
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It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

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Since it asks to calculate the moles that is n, so let's rearrange this for n:

n=\frac{PV}{RT}

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Let's plug in the values in the equation to get the moles.

n=\frac{0.982atm*19.4L}{0.0821\frac{atm.L}{mol.K}*290K}

n = 0.800 moles

So, 0.800 moles of the gas were collected.

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