Answer: The name of the 
is Iodine tetrabromide and it is a covalent compound.
Explanation:
Inter-halogen compounds are compounds which composed of two different halogen atoms. For example ;
etc.
The naming is done by first writing the central atom symbol's name followed by the prefix corresponding to the number of atoms of another halogen atom like: Mono for 1, di ,for 2 tri for 3, tetra for 4 , penta for 5 etc. After this name of the another halogen is written with suffix 'ide' in the end.
The name of the is Iodine tetra bromide.
In halogen compounds, the difference in electronegativities is not so large due to which they form covalent compounds by the means of sharing the electrons. Hence the Iodine tetrabromide covalent compound.
Answer:
The answer is C
Explanation:
An atom is extremely small, but a device to make them look bigger, like a microscope, will help Xavier see it
<h3>1. C</h3><h3>2. D</h3><h3>3.B</h3><h3>4. C</h3><h3>5. D</h3><h3>6. C</h3><h3>7. C</h3><h3>8. C</h3><h3>9. C</h3><h3>10. A</h3><h3>11. Closer and Tightly</h3><h3>12. Slightly and medium</h3><h3>13. Far and motion</h3>
Answer:
40.34 g
Explanation:
First, we divide the heat to release by the heat of combustion to obtain the required moles of compound:
541.20 kJ/(1160.00 kJ/mol) = 0.4665 mol
So, we have to burn approximately 0.47 mol of the compound. We convert the moles to mass in grams by using the molar mass:
mass = molar mass x moles = 86.47 g/mol x 0.4665 mol = 40.34 g
Therefore, you must burn 40.34 grams of the compound to release 541.20 kJ of heat.
