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svp [43]
3 years ago
10

Question 2(Multiple Choice Worth 3 points) What happens to the rate of most reactions as the reaction progresses? The rate remai

ns constant over the course of the reaction. The rate decreases as the concentration of the reactants decreases. The rate increases as the concentration of the products increases. The rate change depends on the energy change of the reaction.
Chemistry
1 answer:
Sav [38]3 years ago
3 0

Answer: -

The rate decreases as the concentration of the reactants decreases

Explanation: -

A reaction involves change of the reactants into products.

Initially there is only reactants. So the rate if reaction is high.

After some time there are products. So the amount of reactant is less.

Reactions involve collisions of reactant molecules. As the reactant amount decreases, collisions between the reactants decreases. As such the rate of reaction decreases with the progress of the reaction.

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What two types of elements are ionic compounds made of?
mash [69]

Answer:

ionic compounds are made from metal and non mental elements

Explanation:

in this case it is know as an ionic compound because it contains a charge. For example, NaCl is simply a compound as it contains no charges (the charges cancel out as Cl is -1 and Na is +1)

but OH- is an ionic compound as it has a charge if -1 (O has a -2 charge and H has a +1 charge, so -2+1=-1 so OH has -1 charge)

8 0
3 years ago
when the following redoc reaction is balances (assume acidic solution), how many moles of water appear and on what side
PolarNik [594]

8 moles of water on the right side.

An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).

Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.

Step 1:

MnO4- ----> Mn2+

2Cl- ------> Cl2

Step 2:

MnO4- --> Mn2+ + 4H2O

2Cl- -----> Cl2

Step 3:

8H+ + MnO4- ------> Mn2+ + 4H2O

2Cl- ----->Cl2

Step 4:

8H+ + MnO4- +5e- ------>Mn2+ + 4H2O

2Cl- ----> Cl2+ 2e-

Step 5:

16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2

This is the balanced equation in an acidic medium.

That is 8, right side.

To know more about redox reaction follow the link:

https://brainly.in/question/9854479

#SPJ4

8 0
2 years ago
If the speed of a sound wave increases what other property of the wave must also increase when all other wave properties are hel
kati45 [8]
<h2>Frequency</h2>

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

Wave speed is the speed at which a wave travels.

Let the wave speed be v

Let the wave frequency be f

Let the wave length be l

The wave speed,frequency and wave length are related by the equation v=f\times l.

When v increases,f increases on the other side to maintain equality when no other property is changing.

8 0
3 years ago
How can all chemical compounds be classified?
ale4655 [162]
Organic or inorganic is the answer
5 0
3 years ago
Read 2 more answers
An unknown compound, X is thought to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 an
Westkost [7]

Answer:

7.3

Explanation:

By Henderson Hasselbalch equation we can calculate the pH or the pOH of a solution by its pKa. Remember that pH = -log[H^{+}], and pKa = -logKa. Ka is the equilibrium constant of the acid.

Henderson Hasselbalch equation :

pH = pKa - log \frac{[HA]}{[A^{-}]}

Where [HA] is the concentration of the acid, and [A^{-}] is the concentration of the anion which forms the acid.

So, acid X, has two ionic forms, the carboxyl group and the other one. First, we have 0.1 mol/L of the acid, in 100 mL, so the number of moles of X

n1 = (0.1 mol/L)x(0.1 L) = 0.01 mol

When it dissociates, it forms 0.005 mol of the carboxyl group and 0.005 mol of the other group. Assuming same  stoichiometry.

Adding NaOH, with 0.1 mol/L and 75 mL, the number of moles of OH^- will be

n2 = (0.1 mol/L)x(0.075 L) = 0.0075 mol

So, the 0.0075 mol of OH^- reacts with 0.005 mol of carboxyl, remaining 0.0025 mol of OH^-, which will react with the 0.005 mol of the other group. So, it will remain 0.0025 mol of the other group.

The final volume of the solution will be 175 mL, but both concentrations (the acid form and ionic form) have the same volume, so we can use the number of mol in the equation.

Note that, the number of moles of the acid form is still 0.01 mol because it doesn't react!

So,

6.72 = pKa - log \frac{0.01}{0.0025}

6.72 = pKa - log 4

pKa - log4 = 6.72

pKa = 6.72 + log4

pKa = 6.72 + 0.6

pKa = 7.3

8 0
3 years ago
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