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spin [16.1K]
3 years ago
12

Solve the equation 28 = 7 3x for x: a. 1 b. 3 c. 5 d. 7

Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0
I think you meant 28=7+3x. Subtract 7 from both sides to get 21=3x, then divide by three to get D. 7

:)
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neonofarm [45]

Answer:

320

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First, convert the percent into a fraction.

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Laura tiene una tarifa de telefono la que paga solo por un tiempo que dura cada llamada si un minuto cuesta 0,08 y su ultima lla
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Answer:

0,252

Step-by-step explanation:

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4 0
3 years ago
Suppose that NOP is isosceles with base.
NemiM [27]

Step-by-step explanation:

<u>In isocseles triangle, base angles </u><u>are</u><u> equal</u> :

base angles are angle N and angle P:

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3x+17=4x+2

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<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>N</u><u>:</u>

subtitute x in angle N

=3(15)+17

=45+17

=62

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subtitute x in angle P:

=4(15)+2

=60+2

=62

<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>O</u><u>:</u>

sum of all angles in a triangle is 180.

angle N +angle P+angle O=180

62+62+angle O=180

angle O=180-62-62

angle O=56

<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u><u> </u><u>i</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>have</u><u> </u><u>any</u><u> </u><u>question</u><u> </u><u>l</u><u>e</u><u>t</u><u> </u><u>m</u><u>e</u><u> </u><u>k</u><u>n</u><u>o</u><u>w</u><u> </u><u>a</u><u>b</u><u>o</u><u>u</u><u>t</u><u> </u><u>i</u><u>t</u><u>.</u><u> </u><u>t</u><u>h</u><u>a</u><u>n</u><u>k</u><u>s</u>

4 0
3 years ago
water main construction a water main is to be constructed with a 20% grade in the north direction and a 10% grade in the east di
ArbitrLikvidat [17]

The value of the angle θ required in the water main for the turn from north to east is 87.40°.

According to the statement

We have to find that the value of the angle.

So, For this purpose, we know that the

An angle is created when two straight lines or rays meet at a standard endpoint.

From the given information:

a main is to be constructed with a 20% grade within the north direction and a tenth grade within the east direction.

Then

Let n = North

and e = east

Then

using vectors,

n =  j + 0.20 k

e = i + 0.25 k

And the

n · e = 1x0 + 0x1 + 0.20×0.25 = 0.05

Now take magnitude then

|n|·|e| = i(1² + 0.20²)·i(1²+0.25²) = 1.105

Now,

E° = arccos((n · e)/|n|·|e|)

E° = arccos(0.05/1.105)

E° = arccos (0.0452)

E° = 87.40°

So, The value of the angle θ required in the water main for the turn from north to east is 87.40°.

Learn more about angle here

brainly.com/question/24368895

#SPJ4

8 0
1 year ago
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