Adam is incorrect because if you substitute the value of y (which is 2) on the expression 52-3y=20, the statement is false since 46 is obviously not equal to 20.
52-3(2)=20
52-6=20
46 = 20
FALSE
Answer:
11) Irrational number
12) Integer
13) Communitive property of addition
14) Distributive property of addition and multipacation
15) 26
16) 8
17) -41
18) 65
19) -5x-20
Step-by-step explanation:
Hope I helped
Step-by-step explanation:
The easiest approach is to realise that one hour is 3 times longer than
20
minutes. The longer the time, the more they will pave.
2
15
of a mile, in 20 minutes, how much in 60 minutes?#
They will pave 3 times more.
2
15
×
3
1
=
6
15
of a mile
6
15
=
2
5
of a mile
You could also use the 'unitary method' where you find out how much they pave in ONE minute (divide by
20
) and them multiply by
60
to find how much in one hour.
Look at what happens:
2
15
÷
20
×
60
=
2
15
×
1
20
×
60
3
=
2
15
×
3
←
exactly the same maths.
=
2
5
Answer:
Hence average rate of change is greater for f(x) in (0,3).
Yes. f(x) is greater than g(x) in the interval (0,3)
Yes. g(3) <f(3)
Step-by-step explanation:
To find average rate of change of f and g in (0,3)
f(3)-f(0)/3 = (9-0)/3 =3
g(3) = -9-18 = -27
g(0) = 0
Rate of change in(0,3) of g(x) = -27/3 =-9
Hence average rate of change is greater for f(x) in (0,3)
---
Both f and g have intercepts of y as 0
Hence both are equal.
3) Yes. f(x) is greater than g(x) in the interval (0,3)
Because g(x) <0 for all x in (0,3) while f(x) >0
4) g(3)= -9-18=-27 <f(3)
- Simplify ⇨ 19m + 14 - 3 (3m + 7)
Use the distributive property to multiply -3 by 3m+7.
Combine 19m and -9m to get 10m.
Subtract 21 from -14 to get -35.
