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satela [25.4K]
2 years ago
6

List two equivalent numbers to 0.50

Mathematics
1 answer:
ad-work [718]2 years ago
8 0
1/2, 4/8. If in decimal form, you can also do 0.5 or 0.500
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What are the domain and range of the function below? domain: (-40)
Mumz [18]

range{-2,00)

Step-by-step explanation:

6 0
3 years ago
Value of the y-intercept of the graph of f(x) = e1–x – 1?
frozen [14]

Answer:

(0, e-1) or (0, 1.718) to the nearest thousandth.

Step-by-step explanation:

The y-intercept occurs when x = 0 so here we have:

y = e^(1 - 0) - 1

= e - 1

So the y-intercept is the point (0, e-1)

5 0
3 years ago
Help this question is due in like 15 minutes :p
fomenos

Answer:

A= 150°

B=30°

C=150°

Step-by-step explanation:

Since a line is 180°, you can write an equation for C. C+30°=180° , from here use algebra to find C. The value of C will be 150°. When the value of C is 150° , since they're supplementary angles, the value of A will also be 150°.

Important thing to note:

The value of all these angles combined together is 360°.

5 0
2 years ago
On a test of 80 problems, Bill got 75% of the problems correct. How many question did he get correct?​
Pavel [41]

Answer: 60

Step-by-step explanation:

75% of 80 is 60.

Multiply 80 by .75 to get the answer.

6 0
3 years ago
The probability for success of an event is P(A), and the probability of success of a second, independent event is P(B). What is
Alborosie

Given:

The probability for success of an event is P(A)

The probability of success of a second, independent event is P(B).

To find:

The probability of both events occurring, in that order.

Solution:

If A and B are two independent events, then

P(A\cap B)=P(A)\cdot P(B)

It is given that,

The probability for success of an event is P(A)

The probability of success of a second, independent event is P(B).

Since A and B both are independent event and we need to find the probability of both events occurring, in that order, i.e., P(A\cap B), therefore P(A\cap B)=P(A)\cdot P(B).

Hence, the correct option is A.

5 0
2 years ago
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