All categories

3 years ago

Is 7/20 and 0.07 equivalent numbers

Mathematics

2 answers:

IceJOKER [234]3 years ago

7 0

$\frac{7}{20}=0.35 \\ 
 \\ \frac{7}{100}=0.07 \\ 
 \\ Solution: No \ they \ are \ not \ equivalent \ fractions \\$

Gelneren [198K]3 years ago

5 0

No, 7/20 and 0.07 are not equivalent numbers because 7/20 equals 0.35 as a decimal which is nowhere equivalent to 0.07

You might be interested in

F(x)=x2 what is g(x)?

Oksi-84 [34.3K]

g(x) = (1/4)x^2 . correct option C) .

Step-by-step explanation:

Here we have , $f(x)=x^2$ and we need to find g(x) from the graph . Let's find out:

We have , $f(x)=x^2$ . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

A . g(x) = (1/4x)^2

Putting (2,1) in equation g(x) = (x/4)^2 , we get :

⇒ $g(2)= (\frac{2}{4} )^2$

⇒ $1\neq \frac{1}{4}$

Hence , wrong equation !

B . g(x) = 4x^2

Putting (2,1) in equation g(x) = 4x^2 , we get :

⇒ $g(2)=4(2)^2$

⇒ $1\neq 64$

Hence , wrong equation !

C . g(x) = (1/4)x^2

Putting (2,1) in equation g(x) = (1/4)x^2 , we get :

⇒ $g(2)= (\frac{1}{4} )2^2$

⇒ $1= 1$

Hence , right equation !

D . g(x) = (1/2)x^2

Putting (2,1) in equation g(x) = (1/2)x^2 , we get :

⇒ $g(2)= (\frac{1}{2} )2^2$

⇒ $1\neq 2$

Hence , wrong equation !

Therefore , g(x) = (1/4)x^2 . correct option C) .

8 0

3 years ago

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

Effectus [21]

Answer:

make x→0

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

Replace x→-1

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

Now make x→2

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

5 0

2 years ago

Solve the quadratic equation 3x²-3x-1=0? (by using the square method)

ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

$3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}$

$x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1$

$x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}$

Therefore, x=1 and x=-1/3

8 0

2 years ago

-6x+6y=6 -6x+3y=-12 How do you solve this problem?

sergij07 [2.7K]

Answer:

That's called system of equations. it is like adding and subtracting.

Step-by-step explanation:

first you want to find x or y. i will choose x. in order to do that you need to put one, ill do the first one but you can do first or second, and change it to negative (-6x+6y=6) or -(-6x+6y=6), changing it to 6x - 6y = -6. then the two x's will be cancled since 6-6 is 0. now you add 6y and 3y, and 6 with -12. get your answer, and do the same thing to y, too. sorry if its a bit confusing, took me a while to learn it too. this is highschool stuff so thats why you will although im im middle too!

3 0

3 years ago

55.563 to the nearest hundredths

zysi [14]

Answer:55.56

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers