Answer:
solution :
in the given figure AB=10.2cm, AC=14cm, AD=DC and AD perpendicular to BC.
now ,
in rt angle tirangle ADC,
angleACD=45 degree, angle DAC=45 degree now,
in triangle ABD,
angle BAD+angleABD+angleADB=180 DEGREE (sum of the sngle of triangle)
angle BAD+75+30=180
angle BAD=180-165 therefore,angle BAD=15
angle BAC =15+45=60
Area of triangle ABC=1/2×AB×AC×SIN 60
=1/2×10.2×14×√3/2
=61.83cm³ ans
2x^4 + 3x^3 - 5x + 6 ÷ x^2 + 3x - 2
= 2x^6 + 3x^5 − 2x^3 − 2x^2 + 6/
x^2
10
using the second equation you can get s=-2. then plugging that into the first you get
-9(-2)-8 = 18-8 = 10
Answer:
x = 46
Step-by-step explanation:
Here, we want to get the value of the angle marked x
From the diagram given , the two angles that are other than x can be gotten from the value of their supplements
Angles on a straight line are supplementary as they add up to 180
Thus, mathematically;
(180-130) + (180-96) + x = 180
50 + 84 + x = 180
x = 180-50-84 = 46
It's name is “isosceles triangle”