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2 years ago

10

ms. bowen and ms mr clifton had 96 zesty coins. they made group of coins to give to teacher with 9 coins in each group. how many

teacher got coins. if ms.bowen and mr clifton gave 3 group of coins to student

1 answer:

arlik [135]2 years ago

5 0

7 teachers because 3 x 9 = 27 and 96 - 27 = 69, 69 divided by 9 is 7 remainder something

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Ratling [72]

Answer:

1. x=27

2. x=11 or x=-7

3. x=4

4. x=1 or $x=\frac{1}{3}$

5. x=12

6. x=11 or x=-1

7. x=8

8. x=3 or x=1

9. $x=\frac{13}{2}$ or x=-4

10.x=7 or x=1

Step-by-step explanation:

For the first 8, the absolute value portion is just substituted in for x, so we can skip some of the repeated work that would occur in these. For the absolute value problems, there are two solutions each. When you remove an absolute value, you have to add a plus or minus to each side and solve for each.

1. $5x+9=144\\5x=135\\x=27$

2. $|3x-6|=27\\3x-6=27\\3x=33\\x=11\\\\3x-6=-27\\3x=-27\\x= -7$

3. $\frac{x}{7-3} =1\\\frac{x}{4} =1\\x=4$

4. $|12x-8|=4\\12x-8=4\\12x=12\\x=1\\\\12x-8=-4\\12x=4\\x=\frac{4}{12} \\\\x=\frac{1}{3}$

5. $\frac{2}{3}x-11=-3\\\frac{2}{3}x=8\\x=\frac{24}{2}\\ x=12$

6. $|2x-10|=12\\2x-10=12\\2x=22\\x=11\\\\2x-10=-12\\2x=-2\\x=-1$

7. $\frac{4x-5}{3} =9\\4x-5=27\\4x=32\\x=8$

8. $|8x-16|=8\\8x-16=8\\8x=24\\x=3\\\\8x-16=-8\\8x=8\\x=1$

9. $|4x-5| +15=36\\|4x-5|=21\\4x-5=21\\4x=26\\x=\frac{26}{4} \\x=\frac{13}{2} \\\\4x-5=-21\\4x=-16\\x=-4$

10. $6|3x-12|-5=49\\6|3x-12|=54\\|3x-12|=9\\3x-12=9\\3x=21\\x=7\\\\3x-12=-9\\3x=3\\x=1$

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3 years ago