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Paul [167]
3 years ago
11

Is the square root of 4 plus the square root of 16 rational

Mathematics
2 answers:
Ahat [919]3 years ago
4 0
Yes because square root of 4 is 2 and square root of 16 is 4. 4+2=6
Allushta [10]3 years ago
3 0
The answer to your question is yes
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How many different sequences of 3 playing cards (from a single 52-card deck) exist?
hichkok12 [17]

There 1,32,600 possibilities to withdrawn 3 different sequence of playing cards from 52 cards.

<h3>What is Permutations?</h3>

A permutation of a set is, loosely speaking, an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements.

Here, total number of cards = 52

         Number of Withdrawn cards = 3

Possibilities of different sequences of 3 playing cards = 52 X 51 X 50

                                                                                          = 132600

Thus, there 1,32,600 possibilities to withdrawn 3 different sequence of playing cards from 52 cards.

Learn more about Permutations from:

brainly.com/question/1216161

#SPJ1

4 0
2 years ago
Terry has a box of 144 colored pencils. If he and 4 of his friends share the pencils equally, how many pencils will be left over
monitta

Answer:

number of people=4+1

=5

144/5=28.5

28×5=140

Step-by-step explanation:

how many pencils will be left over?=144-140

=4

6 0
2 years ago
I need 0.0854 to the nearest hundredth. Is 0.08 to the nearest hundredth or is 0.09?
JulsSmile [24]
0.09 for sure!!!!!!!!!!!!!!!!!!!


8 0
4 years ago
Read 2 more answers
Please help with this
mezya [45]

Answer:

96

Step-by-step explanation:

If B is the midpoint of AC, the length of AC has to be twice the length of AB. This is because AB = AC. Twice 48 is 96.

4 0
3 years ago
P( x) =x^3-6x^2-5x-14 What is the remainder R when the polynomial p(x) is divided by (x-7)
Igoryamba

Answer:

The remainder is zero

Step-by-step explanation:

To find the remainder we will use the long division

\frac{x^{3}-6x^{2}-5x-14}{x-7}=x^{2}\frac{x^{2}-5x-14 }{x-7}⇒(1)

\frac{x^{2}-5x-14}{x-7}=x\frac{2x-14}{x-7}⇒(2)

\frac{2x-14}{x-7}=2⇒(3)

From (1) , (2) and (3)

The quotient of the long division is x^{2}+x+2 and no remainder

So the remainder is zero

* If you want to check your answer Multiply the quotient by the divisor

(x^{2}+x+2)(x-7)=x^{3}-6x^{2}-5x-14

8 0
3 years ago
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