Answer:
65.3658 inches
Step-by-step explanation:
Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value
such that
, but,
, i.e.,
is the 76th percentile of the standard normal distribution. So,
,
. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.
Answer: y= 9x+1
Step-by-step explanation:
Even though I'm only in 7th grade....
Divide 19/2= 9. Something
19-1=18, and 18/2=9
Do the same to others to check