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Rainbow [258]
3 years ago
10

The output is three less than the input

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
Call the output f(x)
Call the input x
f(x) = x - 3
nexus9112 [7]3 years ago
7 0

Answer:

y=x-3

Step-by-step explanation:

We have been given a description. We are supposed to represent our given description in an equation.

We know that input of a function is x values and it is independent variable. The output is y values and it is dependent on x.

The output is three less than the input. We can represent this information in an equation as:

\text{Output}=\text{Input}-3

y=x-3

Therefore, our required equation would be y=x-3.

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Write the following numbers in order from least to greatest,
PIT_PIT [208]

Answer: D

Step-by-step explanation:

Look at the exponents first and order them from least to greatest

5 0
3 years ago
the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const
laiz [17]
In general, the volume

V=\pi r^2h

has total derivative

\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)

If the cylinder's height is kept constant, then \dfrac{\mathrm dh}{\mathrm dt}=0 and we have

\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}

which is to say, \dfrac{\mathrm dV}{\mathrm dt} and \dfrac{\mathrm dr}{\mathrm dt} are directly proportional by a factor equivalent to the lateral surface area of the cylinder (2\pi r h).

Meanwhile, if the cylinder's radius is kept fixed, then

\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}

since \dfrac{\mathrm dr}{\mathrm dt}=0. In other words, \dfrac{\mathrm dV}{\mathrm dt} and \dfrac{\mathrm dh}{\mathrm dt} are directly proportional by a factor of the surface area of the cylinder's circular face (\pi r^2).

Finally, the general case (r and h not constant), you can see from the total derivative that \dfrac{\mathrm dV}{\mathrm dt} is affected by both \dfrac{\mathrm dh}{\mathrm dt} and \dfrac{\mathrm dr}{\mathrm dt} in combination.
8 0
3 years ago
F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

6 0
3 years ago
Pls help me answer this!​
Vadim26 [7]

Answer:

someoeneenennene willlll heelellelelleep yyouuouou

Step-by-step explanation:

stan kim namjoon

8 0
3 years ago
Read 2 more answers
Finding the values of Product and Quotient Functions:
Goshia [24]

Answer:

2

Step-by-step explanation:

r(x) = 2 sqrt(x)

s(x) = sqrt(x)

r(x) / s(x) =  2 sqrt(x) / sqrt(x)

              = 2

8 0
3 years ago
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