What is the absolute value of |-20|+|30|
1 answer:
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$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
We know that
the number
is equal to
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is equal to
divide by 5 both members
therefore
the number is equal to 
the number
is equal to
and
divide by 5 both members
therefore
the number