Answer:
Step-by-step explanation:
61 - (2 4/16 +3 2/3) = 61 - (5 +( 4/16 + 2/3))
= 61 - (5 +( 6/24 + 16/24))
= 61 - (5 + 22/24)
= (61 - 5) - 22/24
= 56 - 11/12
= 55 1/12
A triangle OAB is formed where O is the centre of a cricle of radius 12cm, and A and B are endpoints of a 15cm chord. find the a
ngle subtended at the centre of the circle, in degrees and minutes
1 answer:
We are asked to solve for the angle AOB and we are given with the following values:
radius = 12 cm
length of AB = 15 cm
We can solve for angle AOC such as shown below:
sin AOC = opposite/hypotenuse
sin AOC = 7.5/12
∠AOC =38.68°
The angle subtended at the center of the circle is just twice of ∠AOC, then we have:
∠AOB = 38.68° x 2
∠AOB = 77.36°
The answer is 77° 21' 51.75".
radius = 12 cm
length of AB = 15 cm
We can solve for angle AOC such as shown below:
sin AOC = opposite/hypotenuse
sin AOC = 7.5/12
∠AOC =38.68°
The angle subtended at the center of the circle is just twice of ∠AOC, then we have:
∠AOB = 38.68° x 2
∠AOB = 77.36°
The answer is 77° 21' 51.75".
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