I need help I can’t figure this out

AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A

Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

$\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}$ .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

$\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}$ ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

$\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}$ .....(3)

The area of triangle APM is 35m².

$\text{Area of }\triangle APM=\frac{x}{4}$

$35=\frac{x}{4}$

$x=140$

Therefore the area of triangle ABC is 140m².

Using equation (2).

$\text{Area of }\triangle APC=\frac{x}{2}$

$\text{Area of }\triangle APC=\frac{140}{2}$

$\text{Area of }\triangle APC=70$

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

$\triangle BPC=\triangle BPM+\triangle PMC$

$70=35+\triangle PMC$

$35=\triangle PMC$

Therefore the area of triangle PMC is 35m².

8 0

3 years ago

A ball is dropped from the top of a building that is 250 feet tall. The

Virty [35]

hi

-16t²+250 = 75

-16t² = 75 -250

-16t² = -175

t² = -175 /-16

t² = 175/16

Here there si two solutions : t = $\sqrt{175/16}$ and t = - $\sqrt{175/16}$

However, as time cannot rewind, we will keep only positive solution

So t = $\sqrt{175/16}$

in seconds it will be : 3.3 seconds

3 0

3 years ago

(−2k 3 −7k 2 +5k)+(6k 2 +3k)=

shusha [124]

Answer: 5k +7

Step-by-step explanation: -2k + -7k + 5k is -4K and 2+3=5 -4K +5 and 6k +3k= 9k + 2 then u do -4K plus 9k and get 5k next, 5+2

7 0

2 years ago

The width of a rectangular computer screen is 2 inches more than its height. If the area of the screen is 323 square inches, fin

Lana71 [14]

Width= 19 in
Height= 17 in

WxH=323

19x17=323

5 0

3 years ago

Evaluate 9(4x – 15) if x = 3.

4vir4ik [10]

Answer:

-27

Step-by-step explanation:

9(4x – 15)

Substitute 3 for x

9((4)(3) - 15)

Multiply (4)(3) = 12

9 ( 12 - 15 )

Subtract 12 - 15 = -3

9(-3)

Multiply 9(-3) = -27

5 0

3 years ago

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