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3 years ago

Line t passes through points (10, 4) and (7, 9). Line u is parallel to line t. What is the slope of line u?

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

Answer: 3/5

Step-by-step explanation:

concept to know: the slope of perpendicular line is always opposite reciprocal

----------------------

Step 1. Find the slope of line t

(y2-y1)/(x2-x1)

=(4-9)/(10-7)

=-5/3

-------------------

Step 2. Apply the concept

Opposite reciprocal of (-5/3)=3/5

Hope this helps!! :)

Please let me know if you have any question

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1 year ago

Please help I asked this question earlier and nobody answered! :(

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Answer:

Step-by-step explanation:

One way to tell is to put both equations into slope-intercept form. That form is usually written $y=mx+b$ where m is the slope and b is the y-intercept.

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3 years ago

Which ordered pair is the solution to the system of equations?

Tcecarenko [31]

The best way to answer this item is to use the Substitution method. Substitute the value of y from the first equation to the y of the second equation such that the second equation becomes,

-4x + 3(x - 4) = -3

Simplifying the equation,
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Dividing both sides by -1 gives an answer of,
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Then, substitute the value of x in the first equation.
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3 years ago

Read 2 more answers

Please round to the nearest tenth if possible.

Butoxors [25]

$\bf \cfrac{64~\underline{mi}}{\underline{hr}}\cdot \cfrac{\underline{hr}}{60~sec}\cdot \cfrac{5200~ft}{\underline{mi}}\implies \cfrac{64\cdot 5200~ft}{60~sec}\implies \cfrac{16640~ft}{3~sec}
\\\\\\
\approx 5546.67\frac{ft}{sec}\\\\
-------------------------------\\\\
\cfrac{6000~\underline{lbs}}{\underline{day}}\cdot \cfrac{ton}{2000~\underline{lbs}}\cdot \cfrac{7~\underline{day}}{week}\implies \cfrac{6000\cdot 7~ton}{2000~week}\implies 21.00\frac{ton}{week}$

$\bf -------------------------------\\\\
\cfrac{2~\underline{lbs}}{\underline{week}}\cdot \cfrac{16~oz}{\underline{lbs}}\cdot \cfrac{\underline{week}}{7~day}\implies \cfrac{2\cdot 16~oz}{7~day}\implies \cfrac{32~oz}{7~day}\approx 4.57\frac{oz}{day}$

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