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Gre4nikov [31]
3 years ago
7

I need help with these questions. please respond asap 25 points and brainliest :)

Mathematics
1 answer:
krok68 [10]3 years ago
6 0
Question 5 and 6 are the same.

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Number line for-5 c <-30 the sign also has a line under it
Eddi Din [679]
If you are solving for c you need to divide both sides of the inequality by -5 so c< (or equal to) -30/-5 or c<(or equal to)7
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A 2-feet wide manhole cover is designed to cover a manhole opening on the street.
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Approximately 9.4
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5 0
3 years ago
the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.
Bond [772]

Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d  where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671  = a1 + 42d

-806 = a1 + 51d

Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

-9d =  135

d = -15

Substitute for d in the first equation:

-671 = a1 + 42*-15

-671 = a1 - 630

a1 = -671 + 630 = -41.

3 0
3 years ago
This means that √31 is between
Serggg [28]
5 and 6 (5 being the square root of 25 and 6 being the square root of 36, which are the closest perfect squares)
3 0
3 years ago
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Which method correctly solves the equation using the multiplication property of equality and the reciprocal of One-third? One-th
Airida [17]

Answer:

Step-by-step explanation:

Given the equation \frac{1}{3}(x+9) = -12

Step 1;

Expand the bracket at the right hand side of the equation to have:

\frac{1}{3}x +\frac{1}{3}(9) = -12\\\frac{1}{3}x+3=-12\\subtracting\ 3\ from\ both\ sides\\\frac{1}{3}x+3-3=-12-3\\\frac{1}{3}x=-15\\

Taking the reciprocal of both sides:

\frac{3}{x} = \frac{-1}{15} \\ cross\ multiplying\\-x =45\\x=-45

4 0
3 years ago
Read 2 more answers
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