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2 years ago

I need help on this, I have no idea what I’m doing

Mathematics

1 answer:

Studentka2010 [4]2 years ago

7 0

which problems? i can teach you how to do them if you want me too.

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Prove that this question:.

Vikki [24]

This follows directly from the double angle identity for cosine and the Pythagorean identity:

$\cos2\theta=\cos^2\theta-\sin^2\theta=\begin{cases}2\cos^2\theta-1\\1-2\sin^2\theta\end{cases}$

So we have

$\dfrac{1-2\sin^2\theta}{2\cos^2\theta-1}=\dfrac{\cos2\theta}{\cos2\theta}=1$

8 0

3 years ago

Can someone help me with this bonus question for me

Cerrena [4.2K]

i cant read it well can u type it so i can answer ?

4 0

2 years ago

3. [6x - 2y=2.<br> (2 + 6x=y

Hunter-Best [27]

Answer:

3. [6x - 2y=2.

(2 + 6x=y

Step-by-step explanation:

4 0

2 years ago

Find the distance between the given points (4,1) and (-5, -2)

anyanavicka [17]

Answer:

$3\sqrt{10}$ units I THINK

Step-by-step explanation:

using the distance formula, -2 - 1 = -3

-3 x -3 = 9

-5 - 4 = -9 x -9 = 81

81 + 9 = 90

sqrt 90 simplified is $3\sqrt{10}$ .

so im pretty sure that's the answer.

5 0

2 years ago

18,000 amounts to 21,600 in 4 years at simple interest. Find the sum of

AnnyKZ [126]

Answer:

$\$20,400$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

step 1

Find the rate of interest

in this problem we have

$t=4\ years\\ P=\$18,000\\ A=\$21,600\\r=?$

substitute in the formula above and solve for r

$\$21,600=\$18,000(1+4r)$

$1.2=(1+4r)$

$4r=1.2-1$

$r=0.2/4=0.05$

The rate of interest is $5\%$

step 2

Find the sum of money that will amount to 25,500 in 5 years, at the same rate of interest

in this part we have

$t=5\ years\\ P=?\\ A=\$25,500\\r=0.05$

substitute in the formula above and solve for P

$\$25,500=P(1+0.05*5)$

$P=\$25,500/(1.25)=\$20,400$

3 0

2 years ago