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AVprozaik [17]
2 years ago
13

What is the solution of the equation? w - 2 = -3

Mathematics
1 answer:
Sophie [7]2 years ago
3 0
W - 2 = -3....add 2 to both sides
w - 2 + 2 = -3 + 2...simplify
w = -1 <== ur solution
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Please help me with this trigonometry question. Brainliest available.
faltersainse [42]
Considering the angle a by cosine rule
11^2 =7 ^2 +15^2 - 2(7)(15)cos(a)
When you do the maths,
Cos(a) =153/210 =0.729
a= cos inverse of 0.729
a=43 degrees


Considering angle b
7^2=15^2 +11^2 -2(11)(15) cos(b)
This will result in cos(b) =297/330=0.9
b= cos inverse of 0.9 = 25.8 degrees


Considering angle c
15^2=7^2 +11^2 - 2(11)(7) cos(c)
Cos(c) will be = -55/154 = -0.357
c= cos inverse of -0.357=110.9

Comparing the angles a,b and c,
C is the largest size in the triangle with an angle of 110.9 degrees

Am I right please ??
5 0
2 years ago
1. If 36 donuts cost $15.00, what would be the cost for one 12 donuts?
hram777 [196]

Answer: $5 their are 36 donuts and 12 x 3 is 36 and 5 x 3 is 15

5 0
2 years ago
5a + 3b + c= 40<br> a-3b+2c= -10<br> 14a-2b+3c= 50
aalyn [17]

Answer:

a= 40-3b-c/5

a=-10+3b-2c

a=50+2b-3c/14

Step-by-step explanation:

5a+3b+c-(3b+c)=40-(3b+c)

5a=40-3b-c

5a/5=40/5-3b/5-c/5

a= 40-3b-c/5

a-3b+2c-(3b+2c)=-10-(-3b+2c)

a=-10+3b-2c

14a-2b+3c-(-2b+3c)=50-(-2b+3c)

14a=50+2b-3c

14a/14=50/14+2b/14-3c/14  

a=50+2b-3c/14

8 0
3 years ago
Keith exercises x hours a week. Troy exercises three hours less than Keith and Joe exercises two times more than Troy. Which exp
umka21 [38]
If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3. 
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two. 

Keith = x
Troy = x-3
Joe = 2(x-3)
4 0
3 years ago
Find the 22th term in the arithmetic sequence<br> 23,14,5,-4
Darya [45]

Answer:

-45

Step-by-step explanation: no explanation

3 0
3 years ago
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