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Dennis_Churaev [7]
2 years ago
7

If an event is unlikely to occur , the probability is between ___ and ___ on the probability spectrum .

Mathematics
1 answer:
lianna [129]2 years ago
4 0

Answer:

1% and 49%

Step-by-step explanation:

0% is impossible

1%-49% is unlikely

50% is as likely as not

51%-99% is likely

100% is certain

hope this helps!

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In what follows use any of the following tests: Regression, multiple regression, one-sided t-test, or two-sided t-test. All conc
Vlad [161]

Answer:

1. d. Two sided t-test

2. b. 0.000193

3. a. Since p- value is very small we can conclude that the more soda the student drink the heavier they get.

4.  c. Test in inconclusive; thus we cannot claim that there is a correlation between drinking soda and weight.

Step-by-step explanation:

The hypothesis testing is used to test the claim against the alternative hypothesis. The p value is determined in order to conclude the result for the test as whether to accept or reject the null hypothesis. The null hypothesis can be accepted when the p value is greater than the critical value of the t-test.

8 0
3 years ago
What two same numbers multiply to equal 100
sertanlavr [38]

Answer:

10X10

Step-by-step explanation:

5 0
2 years ago
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Please answer fast for brainliest <br> what is the solution set for the inequality?
tamaranim1 [39]

Answer: F

Step-by-step explanation: I think....

3 0
2 years ago
A basketball team has three pure centers, four pure forwards, four pure guards and one swing- man who can play either guard or f
nadya68 [22]

Answer:

We conclude that he coach can choose  252  lineups.

Step-by-step explanation:

We have three pure centers, four pure forwards, four pure guards and one swing- man who can play either guard or forward.

First case: swing- man play guard.

So now we count the number of combinations: to select from 3 centers 1 center, from 4 forwards to choose 2, and from 4 from the guards to choose 1.

C_1^3\cdot C_2^4\cdot C_1^4=3\cdot \frac{4!}{2!(4-2)!}\cdot 4=12\cdot 6=72

Second  case: swing- man play forward.

So now we count the number of combinations: to select from 3 centers 1 center, from 4 forwards to choose 1, and from 4 from the guards to choose 2.

C_1^3\cdot C_1^4\cdot C_2^4=3\cdot 4\cdot \frac{4!}{2!(4-2)!}=12\cdot 6=72

Third case: swing- man not play.

So now we count the number of combinations: to select from 3 centers 1 center, from 4 forwards to choose 2, and from 4 from the guards to choose 2.

C_1^3\cdot C_2^4\cdot C_2^4=3\cdot \frac{4!}{2!(4-2)!}\cdot \frac{4!}{2!(4-2)!}=3\cdot 6 \cdot 6=108

Now, we get 72+72+108=252.

We conclude that he coach can choose  252  lineups.

3 0
2 years ago
A jeweler is dividing
tatuchka [14]

<em><u>Question:</u></em>

A jeweler is dividing 3/8 of a pound of rubies among 4 lots. What part of a pound will each lot weigh? A.1/4 B.1/8 C.1/16 D.3/32

<em><u>Answer:</u></em>

Option D

Each lot weight \frac{3}{32} part of pound

<em><u>Solution:</u></em>

Given that,

A jeweler is dividing 3/8 of a pound of rubies among 4 lots

To find: part of a pound each lot weigh

From given,

\frac{3}{8} \text{ of a pound } = 4 lots

Let "x" be the part of a pound each lot weigh

Therefore,

\frac{3}{8} \text{ of a pound } = 4 lots\\\\"x" part = 1\ lots

This forms a proportion and solve by cross multiplying

\frac{3}{8} \times 1 = 4 \times x\\\\x = \frac{3}{32}

Thus, each lot weight \frac{3}{32} part of pound

6 0
2 years ago
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