Can someone help me with this?

Josie buys a necklace for $24 which is 80% off. How much was the full price of the necklace

Sedbober [7]

Answer:

4.8

Step-by-step explanation:

6 0

3 years ago

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What is the product? (9 t minus 4)(negative 9 t minus 4) negative 81 t squared minus 16 negative 81 t squared + 16 negative 81 t

liraira [26]

The product is negative 81 t squared + 16 ⇒ 2nd answer

Step-by-step explanation:

The product of two binomials (ax + b)(cx + d), where a, b, c, and d are constant

Multiply (ax) by (cx) ⇒ 1st × 1st
Multiply (ax) by (d) and (b) by (cx) ⇒ ext-reams and nears
Add the two products ⇒ like terms
Multiply (b) by (d) ⇒ 2nd × 2nd

Let us find the product of (9 t - 4) and (-9 t - 4)

Multiply the 1st two terms

∵ (9 t)(-9 t) = -81 t²

Multiply the ext-reams

∵ (9 t)(-4) = -36 t

Multiply the nears

∵ (-4)(-9 t) = 36 t

Add the like terms

∵ -36 t + 36 t = 0

Multiply the 2nd two terms

∵ (-4)(-4) = 16

Write the answer

∴ (9 t - 4)(-9 t - 4) = -81 t² + 0 + 16

∴ (9 t - 4)(-9 t - 4) = -81 t² + 16

The product is -81 t² + 16

Learn more:

You can learn more about the product of algebraic expressions in brainly.com/question/1617787

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7 0

3 years ago

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let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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6 0

1 year ago

Heeelp will give brainliest

ozzi

Answer:

42*7

Step-by-step explanation:

5 0

3 years ago

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If you are asked to provide a set of two or more numeric answers, separate them with commas. For example, to provide the year th

garik1379 [7]

Answer: Perimeter = 66 cm and area = $66\ m^2$

Step-by-step explanation:

The perimeter of rectangle is given by :-

$P=2(l+w)$ , where l is length and w is width of the rectangle.

Given : A rectangle has a length of 5.50 m and a width of 12.0 m .

Then, the perimeter of rectangle :

$P=2(12+5.50)\\\\\Rightarrow\ P=2(17.50)=35\ m$

Also, area of rectangle is given by :-

$A=l\times w=5.50\times12=66 \ m^2$

Area of rectangle = $66\ m^2$

3 0

3 years ago