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Anastasy [175]
4 years ago
15

Which expression is the LCD of these functions? 1/p^3 and 4/7? PLEASE HELP??!?!?!?!?!?!??!?!?!?!?!??!?!?!?!?!?!?!??!?!

Mathematics
1 answer:
ira [324]4 years ago
7 0
LCD stands for least common denominator so you need to find the LCM, least common multiple, of their denominators, p^3 and 7.
Since p is just a variable, multiply the two to find the LCD.
7 x p^3
7p^3
And that is your answer. Hope this helps. 
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Which of the following correctly describes the interval shown?
adoni [48]
B is the correct one
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3 years ago
Solve each system by substitution.<br> 1) y = 2x + 2<br> y = -5x + 16
dalvyx [7]

Answer:

y = 6

x = 2

Step-by-step explanation:

rearrange the first equation in terms of x

x = (y - 2)/2

substiute x in the second equation

y = -5[(y-2)/2] +16

Now simpilify and solve for y

y = (-5y + 10)/2 +16

y = -5/2y + 5 + 16

y + 5/2y = 5 + 16

3.5y = 21

y = 6

Now substitue y in the first equation to solve for x

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5 0
3 years ago
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zepelin [54]

Answer:

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Step-by-step explanation:

The value of x is 6°.

5 0
3 years ago
A new truck costs $32,000 if the truck is worth 24,500 after three years write an explicit formula for the value of the car afte
Debora [2.8K]

Answer:

Step-by-step explanation:

depreciation for three years = 32000 - 24500 = $ 7500

depreciation per year = 7500/3 = $ 2500

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Value of truck after n years = 32000 * (7.81%)*n

8 0
3 years ago
How do u solve two points using the distance formula?
aliya0001 [1]

Step-by-step explanation:

For two points (x₁, y₁) and (x₂, y₂), the distance between them is:

d² = (x₁ − x₂)² + (y₁ − y₂)²

The order of points 1 and 2 don't matter.  You can switch it:

d² = (x₂ − x₁)² + (y₂ − y₁)²

This is basically the Pythagorean theorem for a coordinate system.

Let's do an example.  If you have points (1, 2) and (4, 6), then the distance between them is:

d² = (4 − 1)² + (6 − 2)²

d² = 3² + 4²

d² = 9 + 16

d² = 25

d = 5

If you have points with negative coordinates, remember that subtracting a negative is the same as adding a positive.

For example, the distance between (-1, -2) and (4, 10) is:

d² = (4 − (-1))² + (10 − (-2))²

d² = (4 + 1)² + (10 + 2)²

d² = 5² + 12²

d² = 25 + 144

d² = 169

d = 13

3 0
3 years ago
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