Question

How many pounds of oranges do the data in the plot line represent?

Answer 1

Answer:

OPTION C: $\textbf{37} \frac{\textbf{28}}{\textbf{8}}$ pounds.

Step-by-step explanation:

From the figure we can see that there are three dots against $3 \frac{7}{8}$.

That means it becomes $3 \times 3\frac{7}{8}$.

Note that if there is a mixed fraction of the form $a \frac{b}{c}$   =   $a + \frac{b}{c}$.

Therefore, $3 \times 3\frac{7}{8} = 3 \times \bigg(3 + \frac{7}{8} \bigg )$                ... (1)

Similarly, against 4 there are 2 dots.

So, it should be $4 \times 2$ pounds.                   ...(2)

3 dots against $4 \frac{1}{8}$.

So, it becomes $3 \times \bigg(4 + \frac{1}{8} \bigg)$                       ...(3)

Similarly, 2 dots against $4 + \frac{2}{8}$.

This will become $2 \times \bigg( 2 + \frac{2}{8} \bigg)$                  ...(4)

Now, to calculate the total pound, we simply add (1), (2), (3) & (4).

⇒    $3 \times \bigg(3 + \frac{7}{8} \bigg )$     $+$      $4 \times 2$       +     $3 \times \bigg(4 + \frac{1}{8} \bigg)$       $+$        $2 \times \bigg( 2 + \frac{2}{8} \bigg)$

⇒    $9 + \frac{21}{8} + 8 + 12 + \frac{3}{8} + 8 + \frac{4}{8}$

⇒    $\bigg ( 9 + 8 + 12 + 8 \bigg) + \bigg( \frac{21 + 3 + 4}{8} \bigg )$

⇒ $\textbf{37} \textbf {+} \frac{\textbf{28}}{\textbf{8}}$  $\textbf{=} \hspace{1mm} \textbf{37} \frac{\textbf{28}}{\textbf{8}}$ which is the required answer.