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frez [133]
3 years ago
9

The value of y varies directly with the value of x, and y = –21 when x = 3.

Mathematics
2 answers:
kotykmax [81]3 years ago
5 0

Answer:

<h2><u>X=17</u></h2><h2><u>Y=62</u></h2>

"HOPE THIS HELPS YOU!!"

MrMuchimi3 years ago
4 0
Directly means when x goes up by 3 then y goes up by 3
it is represented by
y/x=k where k stay the same
so y=-21
x=3

the equation is -21/3=-7
k=-7

so k =-7

therfor
y/x=-7
then manipulate the equation
multiply boht sides by x
y=-7x
subsitute valuse for x and get values for y
 if (x,y)
(1,-7)
(2,-14)
(3,-21)

so posiible equationscould be
-7/1=-7
-14/2=-7
-21/3=-7
and so on
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alina1380 [7]
<span>The equations that show a direct variation between x and y when solved for y are:

</span><span>A. -10+y=3x-10
B. y=-1/8x
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Since k is constant (the same for every point), we can find k when given any point by dividing the y<span>-coordinate by the </span>x<span>-coordinate. For example, if </span>y varies<span> directly as </span>x , and y<span> = 6 when </span>x<span> = 2 , the constant of </span>variation<span> is k = = 3 . Thus, the equation describing this </span>direct variation<span> is </span>y<span> = 3x .</span>
7 0
4 years ago
Read 2 more answers
Problem #1: Mrs. Grape has 90 students. On her last test, 3/10 of these students earned an A. Of those students, 1/9 got a perfe
ser-zykov [4K]

Answer:

3 students got a perfect score.

Step-by-step explanation:

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Number of students who earned an A = 3/10 of 90

= \frac{3}{10}\times 90

= 27 students

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5 0
3 years ago
Math help :) pleasee , and thnx
mylen [45]

Answer:

The ball is in the air for approximately 3.27 seconds ⇒ answer A

Step-by-step explanation:

* Lets explain how to solve the problem

- The height of the ball is modeled by the function

  h(t) = -4.9 t² + 16 t

- We need to find the time that the ball is in the air

- The ball is in the air from its initial position and then return to the

   same position

- That means h(t) = 0 because h(t) represent the height of the ball

  from its initial position

∵ h(t) = -4.9 t² + 16 t

∵ h(t) = 0

∴ 0 = -4.9 t² + 16 t

- Add 4.9 t² to both sides

∴ 4.9 t² = 16 t

- Subtract 16 t from both sides

∴ 4.9 t² - 16 t = 0

- Take t as a common factor

∴ t (4.9 t - 16) = 0

- Equate each factor by 0

∴ t = 0 and 4.9 t - 16 = 0

∵ 4.9 t - 16 = 0 ⇒ add 16 for both sides

∴ 4.9 t = 16

- Divide both sides by 4.9

∴ t = 3.2653

∴ t = 0 ⇒ initial position

∴ t = 3.2653 seconds ⇒ final position

* <em>The ball is in the air for approximately 3.27 seconds</em>

6 0
4 years ago
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