S + a = 300...s = 300 - a
8s + 12a = 3200
8(300 - a) + 12a = 3200
2400 - 8a + 12a = 3200
-8a + 12a = 3200 - 2400
4a = 800
a = 800/4
a = 200 <==== 200 adult tickets
s = 300 - a
s = 300 - 200
s = 100 <=== 100 student tickets
Ok
first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0
then simplify
any factors you factored out is now a hole, remember them
to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve
so
y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0
no factors to simplify so no holes
set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1
x+1=0
x=-1
the horizontal assemtotes are x=1 and -1
Answer:
Step-by-step explanation:
here you go mate'
step 1
11 = y-6 equation
step 2
11+6=y-6+6 add 6 to the sides
answer
y=17
can i get brainliest if you dont mind?
Answer:
idk
Step-by-step explanation:
how about you do the math yourself
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
