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4 years ago

6

Solve the equation. If there is not solution, write no solution. 4 times the absolute value of the quantity x plus one third end

of quantity equals 20

1 answer:

stich3 [128]4 years ago

6 0

Answer:

The two solutions to the equation are x = 14/3 or x = -16/3

Step-by-step explanation:

To find these values, go through the steps of solving an equation as if the absolute value symbol is just a parenthesis.

4|x + 1/3| = 20

|x + 1/3| = 5

Now that we have it down to just this, we know what is inside the absolute value symbol to be either +5 or -5. So we need to solve this twice using each option.

x + 1/3 = 5

x = 14/3

x - 1/3 = -5

x = -16/3

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At a college, 7 out of 10 students work either a full-time or a part-time job in addition to their studies. If 4900 students wer

Rina8888 [55]

Answer:

1470 students do not have a full-time or part-time job

Step-by-step explanation:

We have a relationship between students who have a part-time job and those who do not. The ratio is 7 out of 10 students.

Then we use this relationship as a conversion factor.

If of 10 students, 7 of them have a job, then of 4900 students, how many of them have a job?

$4900 * \frac{7}{10}=3430$ students

Finally, those who do not have a job are:

$4900- 3430 = 1470$

3 0

3 years ago

Please do in full working out

TiliK225 [7]

Answer:

0.09022

Step-by-step explanation:

this is basically about knowing how far to move the decimal point.

the decimal point is moved 4 places plus one place = 5 places to the left. so in the answer (9022) you must simply move the decimal place 5 to the left:

0.09022

4 0

3 years ago

17st - 16s + t =<br><br> I NEED HELP

Arisa [49]

It has to be in alphabetical order so, -16s + 17st + t I believe. If it’s incorrect, that’s because we’re barely learning it, sorry.

3 0

4 years ago

Answer the following questions

Alex787 [66]

Answer:

1. $2 \frac{2}{7}$

2. $2 \frac{1}{3}$

3. $\frac{5}{12}$

4. $8 \frac{2}{3}$

5. $\frac{2}{3}$

Step-by-step explanation:

<h2> $1. \: \: 2 \frac{2}{3} \div 1 \frac{1}{6}$ </h2>

$\frac{8}{3} \div \frac{7}{6}$

$\frac{8}{3} \times \frac{6}{7}$

$8( \frac{2}{7} )$

$\frac{8 \times 2}{7}$

$\frac{16}{7}$

$2 \frac{2}{7}$

<h2> $2. \: \: 6 \frac{2}{3} \div 2 \frac{6}{7}$ </h2>

$\frac{20}{3} \div \frac{20}{7}$

$\frac{20}{3} \times \frac{7}{20}$

$\frac{1}{3} \times 7$

$\frac{7}{3}$

$2 \frac{1}{3}$

<h2> $3. \: \: 4 \frac{1}{6} \div 10$ </h2>

$\frac{25}{6} \div \frac{10}{1}$

$\frac{25}{6} \times \frac{1}{10}$

$\frac{5}{6} \times \frac{1}{2}$

$\frac{5}{6 \times 2}$

$\frac{5}{12}$

<h2> $4. \: \: 6 \frac{1}{2} \div \frac{3}{4}$ </h2>

$\frac{13}{2} \div \frac{3}{4}$

$\frac{13}{2} \times \frac{4}{3}$

$13( \frac{2}{3} )$

$\frac{13 \times 2}{3}$

$\frac{26}{3}$

$8 \frac{2}{3}$

<h2> $5. \: \: 3 \frac{3}{4} \div 5 \frac{5}{8}$ </h2>

$\frac{15}{4} \div \frac{45}{8}$

$\frac{15}{4} \times \frac{8}{45}$

$\frac{1}{4} \times \frac{8}{3}$

$\frac{2}{3}$

<h3>Hope it is helpful...</h3>

8 0

3 years ago

File:///C:/Users/legen/Downloads/Pre10%20Radical%20Review%20Packet%20-%20Student%20Handout%20(1).pdf

Vaselesa [24]

Answer:

I am very confused... what is the question?

8 0

3 years ago

Read 2 more answers