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3 years ago

Find the unit rate. (Round to the nearest hundredth, if necessary.) $140 for 18 oz

Mathematics

1 answer:

qwelly [4]3 years ago

3 0

Answer:

OK, the nearest hundredth for 140 is 100.

Step-by-step explanation:

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The low temperature was 35 f. This was 13 f lower than the daytime high temperature. Write an equaton to determin wheter the hig

alina1380 [7]

If x is the high temperature, you can write the following equation:
x = 35°F + 13°F

Which simplifies to:
x = 48°F

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4 years ago

The narrower the confidence interval, the more informative it is. What are the two main ways in which this can be achieved?

Mama L [17]

2 ways:

1. <span>narrow confidence interval

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4 years ago

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Solve the simultaneous equations 2x-y=7 3x+y=3

Debora [2.8K]

Answer:

Step-by-step explanation:

Using elimination method:

2x - y = 7

3x + y = 3

--------------

5x = 10

Divide both sides of the equation by 5

$\frac{5x}{5} = \frac{10}{5}$

Calculate

$x = 2$

Now, substitute the given value of X in the equation

3x + y = 3

$3 \times 2 + y = 3$

Multiply the numbers

$6 + y = 3$

Move constant to R.H.S and change it's sign

$y = 3 - 6$

Calculate

$y = - 3$

The possible solution of this system is the ordered pair ( x , y )

---------------------------------------------------------------------

Check if the given ordered pair is the solution of the system of equation

$2 \times 2 - ( - 3) = 7$

$3 \times 2 - 3 = 3$

Simplify the equalities

$7 = 7$

$3 = 3$

Since all of the equalities are true, the ordered pair is the solution of the system

Hope this helps..

Best regards!!

4 0

3 years ago

NEED HELP WITH NUMBER 3

Reptile [31]

1) 5.028 × 10^21
2) 8.46 × 10^22 (ig theres literally nothing else it could be)
3) approx. 17 times greater (rounded up from 16.8)

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3 years ago

What is the area of this polygon? Enter your answer in the box. units²

Gemiola [76]

Answer:

The area of the polygon is $39\:units^2$

Step-by-step explanation:

Sketch the polygon to obtain the figure in the attachment.

The polygon can then be divided into a rectangle and a triangle.

The area of the polygon

$=|VE|\times |DE|+\frac{1}{2}\times |DE|\times |AM|$

We use the absolute value method to find the lengths

$=|3--2|\times |3--3|+\frac{1}{2}\times|3--3|\times |5-2|$

$=5\times 6+\frac{1}{2}\times 6\times 2$

$=30+9$

$=39\:units^2$

4 0

4 years ago

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