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Alenkinab [10]
3 years ago
5

How do you express to 24.357 in unit form

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0
Twenty ten thousandths, Four thousandths, Three hundredths,Five tens,Seven Ones
Colt1911 [192]3 years ago
6 0
(2*10)+(4*1)+(3*1/10)+(5*1/100)+(7*1/1000)
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The length of the hypotenuse of a right triangle is 16 inches. If the length of one leg is 5 inches, what is the approximate len
Temka [501]
About 15 inches- by pythag- \sqrt{16^{2} - 5^{2} }
6 0
3 years ago
Read 2 more answers
3 out of 5 picks are orange. If 12 picks are orange, has many picks are there in all.
hodyreva [135]
If 3 out of 5 are oranges, this means the ratio is 3 oranges for every 5 total.

If there are 12 oranges, this is 4 groups of 3 oranges.  You will need 4 groups of 5 total to make it equivalent.

4 x 5 = 20 total fruit.

<u>3</u> x <u>4 </u>=  <u>12</u>
5 x 4     20
7 0
3 years ago
Read 2 more answers
A pile of 10 000 paper is 89 cm thick. How thick is one sheet of paper?
Iteru [2.4K]

Answer:

0.0089 cm

Step-by-step explanation:

89/10 000

=0.0089

8 0
3 years ago
0.4 x 10 =....<br>1.25 x 10 = <br>97.465 x10 =​
chubhunter [2.5K]

Answer:

0.4 × 10 = 4

1.25 × 10 = 12.5

97.465 × 10 = 974.65

3 0
3 years ago
NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)
olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level       PA (men)      PA (Women)

Sedentary              1.00                1.00

    Low                    1.11                1.12

  Active                   1.25                1.27

Very Active              1.48                1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

        = 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0
3 years ago
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