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Lina20 [59]
3 years ago
12

A bag contains 3 red apples and 6 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

and 2 yellow apple.
Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Step-by-step explanation:

number \: of \: ways \: to \:  select \: 3 \: out \:   of \:  9 =  {C}^{9}_3  = 84

ways \: to \: select \: 1red \: and \: 2yellow \: apples \:  =  {C}^{3}_1 \times  {C}^{6}_2 = 3 \times 15 = 45

<u>Probability of selecting 1 red and 2 yellow apples</u> = 45 / 84 = 0.53

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Answer:

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Step-by-step explanation:

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sveticcg [70]

Answer:

\frac{x}{y}=1.3

Step-by-step explanation:

<u>Informação recuperada:</u>

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é

1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:

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\frac{x}{y}=\frac{1.3y}{y}\Rightarrow \frac{x}{y}=1.3

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