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adoni [48]
3 years ago
11

Unstable traffic flow occurs when drivers accelerate and brake too often. Unstable traffic flow wastes energy. The table below g

ives one example of traffic speeds, in
lometers per hour
), man
o
Time (p.m.)
Speed (km/h)
4.00
30
4.10
20
4:20
50
4:30
70
4:40
20
4:50
7 0
5:00
20
What is the mean speed, in km/h, in this situation?
You may use the calculator
A 20
B 30
C 40
D 50
Chemistry
1 answer:
maksim [4K]3 years ago
3 0
The answer is B because of the calculator
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Alla [95]

Answer:

Explanation:

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Use the periodic to fill in the numbers in the electron configurations shown below.
puteri [66]

the answers are actually

C=2

D=6

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4 0
3 years ago
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What is the molecular equation for the reaction of solid calcium carbonate with aqueous acetic acid.
malfutka [58]

Answer:

The molecular equation for the reaction of CaCO₃ with CH₃COOH is:

CaCO₃ (s) + 2CH₃COOH (aq) → Ca(CH₃COO)₂ (aq) + H₂O (l) + CO₂ (g)

Option 1

Explanation:

CaCO₃ + 2CH₃COOH → Ca(CH₃COO)₂ + H₂O + CO₂

Option 3 is the same equation as option 1, but calcium acetate, does not precipitate, so the formed salt, is not a solid.

Option 2 and 4 are wrong because calcium acetate molecular formula is

Ca(CH₃COO)₂

Ca(CH₃COO)₂  → Ca²⁺  +   2 CH₃COO⁻

5 0
3 years ago
Measurements show that unknown compound X has the following composition:
zvonat [6]

Answer: The empirical formula of X is C_{5}H_4O_2.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 62.4 g

Mass of H = 4.19 g

Mass of O = 33.2 g

Step 1 : convert given masses into moles.

Moles of C=\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{62.4g}{12g/mole}=5.2moles

Moles of H=\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.19g}{1g/mole}=4.19moles

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{33.2g}{16g/mole}=2.1moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{5.2}{2.1}=2.5

For H =\frac{4.19}{2.1}=2

For O =\frac{2.1}{2.1}=1

The ratio of C: H: O = 2.5 : 2 : 1

Converting it into simple whole number ratios by multiplying by 2:

Hence the empirical formula of X is C_{5}H_4O_2.

6 0
3 years ago
Write the balanced equation for the production of oxygen gas and potassium chloride from the decomposition of potassium chlorate
marishachu [46]

Answer:

2KClO₃→3O₂ + 2KCl

Explanation:

When Potassium Chlorate decomposes , the resulting products are oxygen gas and Potassium chloride . As per the equation above

6 0
3 years ago
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