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mel-nik [20]
3 years ago
14

PLEAS HELP!!! Examine the graph.

Mathematics
2 answers:
raketka [301]3 years ago
7 0
Similarly to the last graph that decreased, this one increases, so you have to see where the line points upwards into the right top corner
CD
frosja888 [35]3 years ago
4 0
Here, x is increasing in two phases, 
-3 < x < -2 Also, 
2 < x < 3

In short, Your Answers would be Option C & D

Hope this helps!
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Help!! <br>2x+3 (x-4)=x-20
prohojiy [21]
Remember  you can do anything to an equation as long as you do it to both sides

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8 0
3 years ago
(05.02)How many triangles can be made if one angle is 95° and another angle is obtuse? 1 2 More than 2 None
Firlakuza [10]

D. None. Say the obtuse angle is 100 degrees. Since the sum of all angles in a triangle cannot be bigger than 180, it's not possible because 195 (100+95) is greater than 180 degrees.


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3 0
3 years ago
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If 4 pounds of potatoes costs $6.78. How much does 1 pound of potatoes cost? Show all your work!
baherus [9]
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3 0
3 years ago
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
2 years ago
Write a subtraction fact with the same difference as 16 -7
hoa [83]
14-5=9, 12-3=9, 15-6=9
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3 years ago
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