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Kazeer [188]
3 years ago
10

What is the value of the expression |a + b| + |c| when a = –3, b = 7, and c = –15?

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
We know:
|a|=  \left\{\begin{array}{ccc}a&if\ a \ \textgreater \  0\\0&if\ a=0\\-a&if\ a \ \textless \  0\end{array}\right\\\\|2|=2\\|0|=0\\|-3|=3

|a+b|+|c|
substitute a = -3; b = 7; c = -15
|-3+7|+|-15|=|4|+15=4+15=19

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R (-3,1) and S (-1,3) are points on a circle. If RS is a diameter, find the equation of the circle.​
ELEN [110]

Answer:

\sf (x+2)^2+(y-2)^2=2

Step-by-step explanation:

If RS is the diameter of the circle, then the midpoint of RS will be the center of the circle.

\sf midpoint=\left(\dfrac{x_s-x_r}{2}+x_r,\dfrac{y_s-y_r}{2}+y_r \right)

             \sf =\left(\dfrac{-1-(-3)}{2}+(-3),\dfrac{3-1}{2}+1 \right)

             \sf =(-2, 2)

Equation of a circle:   \sf (x-h)^2+(y-k)^2=r^2

(where (h, k) is the center and r is the radius)

Substituting found center (-2, 2) into the equation of a circle:

\sf \implies (x-(-2))^2+(y-2)^2=r^2

\sf \implies (x+2)^2+(y-2)^2=r^2

To find \sf r^2, simply substitute one of the points into the equation and solve:

\sf \implies (-3+2)^2+(1-2)^2=r^2

\sf \implies 1+1=r^2

\sf \implies r^2=2

Therefore, the equation of the circle is:

\sf (x+2)^2+(y-2)^2=2

4 0
2 years ago
4 movie tickets cost $48. At this rate with is the cost of 5 movie tickets
cupoosta [38]
60 dollars, because each movie ticket cost 12$.
4 0
3 years ago
Read 2 more answers
Fill in the gaps in the arithmetic sequence -3, _ ,_ , _, _, _ 12
lord [1]

Answer:

  -0.5, 2, 4.5, 7, 9.5

Step-by-step explanation:

The given terms are 6 apart, so the common difference is 1/6 of their difference:

  d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5

Add 2.5 to each term to get the next one. Then the sequence is ...

  -3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12

8 0
3 years ago
Find the unknown length in the right triangle 27cm and 13 cm
Phoenix [80]

use pythagoras:

{c}^{2}  = \:   {b}^{2}  -  {a}^{2}

c^2 = (27)^2 - (13)^2

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3 0
3 years ago
Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
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