Question

A 3.0 L container holds a sample of hydrogen gas at 300 K and 101.5 kPa . The pressure increases to 305 kPa and the volume remains constant. What will the temperature be?

Answer 1

Answer:

The temperature of the Hydrogen gas at pressure $305\ kPa$ is $901.4\ K$.

Explanation:

Given the volume of the Hydrogen gas remain constant.

And the initial temperature and pressure are $T_1=300\ K\ and\ P_1=101.5\ kPa$

We need to find the temperature $(T_2)$ of the gas at $P_2=305\ kPa$

We will use the gas equation to find out that temperature. As the volume is constant we can write with pressure and temperature.

$\frac{P_1}{T_1}=\frac{P_2}{T_2}\\ \\T_2=\frac{P_2}{P_1}\times T_1\\\\T_2=\frac{305}{101.5}\times 300\\ \\T_2=3.004\times 300\\T_2=901.4\ K$

The temperature of the Hydrogen gas at pressure $305\ kPa$ is $901.4\ K$.