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3 years ago

A. Element X has a

1 answer:

8 0

The mass is written as a superscript and the charge is written as a subscript in the isotope notation of element X as follows $\frac{292}{119} X$ .

The isotope notation may also be called the nuclear notation of an element. It helps us to identify what element is represented. It usually comprises of the atomic mass of the element written as a superscript and then the atomic number or charge written as a subscript.

In this case, we have an element with an mass of 292 amu and charge of 119. In this case, the isotope notation of element X is $\frac{292}{119} X$ .

Learn more: brainly.com/question/5838915

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A box contains 104 gas molecules, 2500 of nitrogen and 7500 of argon in thermal equilibrium. The molecular weight of N2 is 28g/m

LekaFEV [45]

Answer : The temperature of this gas will be, 206.9 K

Explanation :

The expression for the kinetic energy per molecule of monoatomic gas (argon) is:

$K.E_{argon}=n_{argon}\times \frac{3}{2}\times K_BT$ ...........(1)

The expression for the kinetic energy per molecule of diatomic gas (nitrogen gas) is:

$K.E_{nitrogen}=n_{nitrogen}\times \frac{5}{2}\times K_BT$ .............(2)

The total kinetic energy of the molecule will be,

$K.E_{Total}=K.E_{argon}+K.E_{nitrogen}$

Now put all the expression in this, we get:

$K.E_{Total}=(7500)\times \frac{3}{2}\times K_BT+(2500)\times \frac{5}{2}\times K_BT$

$T=\frac{K.E}{17500\times K_B}$

Now put all the given values in this expression, we get:

$T=\frac{5\times 10^{-17}J}{17500\times (1.381\times 10^{-23}J/K)}$

$T=206.9K$

Therefore, the temperature of this gas will be, 206.9 K

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4 years ago

Please compare between physical and chemical properties of matter<br>

stealth61 [152]

Answer:

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Explanation:

I got this from chem.libretexts.org in case you wanted to know

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