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mario62 [17]
3 years ago
6

The following flow diagram shows the various steps of elimination of waste through urine. There is an error in one of the steps.

Chemistry
2 answers:
CaHeK987 [17]3 years ago
7 0

Answer:

The answer is A: step one should be urine flows from the kidneys to the ureters.

Explanation:

Ilia_Sergeevich [38]3 years ago
3 0

Answer:

hello pa point lang po

Explanation:

sorry

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PLEASE HELP, will mark brainlest
Shkiper50 [21]

The missing element  : ₇¹⁴N

<h3>Further explanation</h3>

Given

Reaction

₆¹⁴C ⇒X + ₋₁⁰e

Required

The missing element

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

In a decay reaction, the sum of the mass number and atomic number before and after the decay is the same.

The element X :

Atomic number = 6 + 1 =7

Mass number = 14 + 0 = 14

6 0
3 years ago
Jordan is doing a science fair project on the effects of music on the growth of tomatoes. He has two tomato plants, Plant A and
algol [13]
The control group is the plant without the music because nothing is being done to it. while the experimental group is the plant with music because you are testing it in a different environment (the music).
6 0
3 years ago
Read 2 more answers
"The pH of a solution of household ammonia, a 0.950-M solution of NH3, is 11.612. What is Kb" for NH3
aalyn [17]

Answer:

Kb = 1.77x10⁻⁵

Explanation:

When NH₃, a weak base, is in equilibrium with waterm the reaction that occurs is:

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

And the dissociation constant, Kb, for this equilibrium is:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

To find Kb you need to find the concentration of each species. The equilibrium concentrations are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

<em>Where X is reaction coordinate.</em>

You can know [OH⁻] and, therefore, X, with pH of the solution, thus:

pH = -log [H⁺] = 11.612

[H⁺] = 2.4434x10⁻¹²

As 1x10⁻¹⁴ = [H⁺] [OH⁻]

1x10⁻¹⁴ / 2.4434x10⁻¹² = [OH⁻]

4.0926x10⁻³ = [OH⁻] = X

Replacing, concentrations of the species are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

[NH₃] = 0.9459M

[NH₄⁺] = 4.0926x10⁻³M

[OH⁻] = 4.0926x10⁻³M

Replacing in Kb expression:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Kb = [4.0926x10⁻³M] [4.0926x10⁻³M] / [0.9459M]

<h3>Kb = 1.77x10⁻⁵</h3>
7 0
3 years ago
Balance the following equation:<br> Sg + F2 --&gt; SF
Tanzania [10]

Answer:

S+ F2 ⇒ SF

S=1

F =2

So S +F2 ......... 2SF

2S + F2 ..........2SF this is a balance equation

S=2 F=2 in left side s=2 F = 2 in rightside

Explanation:⇆

⇒

3 0
3 years ago
Use the following image to answer the following questions. A student was performing an experiment using two identical cups made
Anettt [7]

Answer:

The water will eventually become the same temature (A)

3 0
3 years ago
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