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lana [24]
3 years ago
5

See the attachment that has the questions and selections.

Mathematics
1 answer:
podryga [215]3 years ago
3 0

The two quantities are equal

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Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
4 years ago
Read 2 more answers
What is the value of (y^-5/x^-3) for x = 2 and y = -4
Anastasy [175]
-1/1024)/(1/8
-1/1024)x 8
-8/1024
-1/128
5 0
3 years ago
Will someone please explain how to do
MrRissso [65]
Distribute the negative first -7c+18-2>0
simplify -7c+16>0
subtract 16 both sides -7c>-16
divide by -1
MOST IMPORTANT PART
when you divide both sides by -1, you HAVE to change the greater/less than sign
so -7c>-16 becomes 7c<16
now divide by 7
c<16/7
I hope you don't yet want to graph it, because graphing is something that's a bit harder to show here

6 0
3 years ago
Which of the following is the best estimate for the total change in distance from the group of​ students' original position at t
ahrayia [7]

Answer:

- 20 feet

Step-by-step explanation:

4 0
4 years ago
Help me LAMOOAAOOOA ‍♀️
Genrish500 [490]

Answer:

17472

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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