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drek231 [11]
2 years ago
15

Roger completed a probability experiment with a coin. He flipped the coin 32 times, and it landed on tails eight times. He looke

d at the results of his experiment to determine the ratio of heads outcomes to tails outcomes.
The ratio of heads to tails in simplified form is _ to _
can somebody help me plz :(
Mathematics
2 answers:
pav-90 [236]2 years ago
8 0

1 to 3

Since you know that he landed on tails 8 out of 32 times, he must have flipped heads for the flips he did not flip tails. So, subtract 32 minus 8, which equals 24, and your answer is 8 to 24. Simplify this like you would with a fraction; the greatest common factor is 8 so divide the "numerator" and the "denominator" by 8. Therefore your final answer is 1 to 3.

pav-90 [236]2 years ago
7 0

Answer:3:1

Step-by-step explanation:

Total number of times he flipped the coin =32 times

Out of the 32 times, the outcome of tails is 8 times

The outcome of heads will be

Total times- Tails outcome

32-8

=24 times

Tails outcome= 8 times

Heads outcome= 24 times

Ratio of heads to tails is

Total heads outcome/total tails outcome

=24/8

=3/1

Therefore ratio of heads to tails is 3:1

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2264253

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}


Trigonometric substitution:

\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}


then,

\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}


So the integral \mathsf{(ii)} becomes

\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}


Integrate \mathsf{(ii)} by parts:

\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}

\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}


Substitute back for the variable x, and you get

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I hope this helps. =)


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