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kherson [118]
3 years ago
6

Which number has an absolute value that is equal to the absolute value of 32?

Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer:

-32

Step-by-step explanation:

The absolute value of a number is its distance from 0. Since distance is always positive the absolute value is the same number but positive. So the absolute value of -32 and 32 would both be 32 because they have the same distance from 0.

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Solve |z| > (1/2)
Anestetic [448]

Answer:

{z|z}U{z|z>\frac{1}{2}}

Step-by-step explanation:

Given the inequality |z| > \frac{1}{2} you need to set up two posibilities:

FIRST POSIBILITY : z>\frac{1}{2}

SECOND POSIBILTY: z

Therefore, you got that:

z\frac{1}{2}

Knowing this, you can write the solution obtained in Set notation. This is:

Solution: {z|z}U{z|z>\frac{1}{2}}

8 0
3 years ago
440 callories in 4 servings; 300 serving in 3 servings
monitta
110 calories in the first one for ONE serving.

100 calories in the second one for ONE serving.

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Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square  of Mx - Ly. In other words

\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy =  \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

  • M(x,y) = 4x²y
  • Mx(x,y) = 8xy
  • L(x,y) = 10y²x
  • Ly(x,y) = 20xy
  • Mx - Ly = -12xy

Therefore, the line integral can be computed as follows

\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy

Using the linearity of the integral and Barrow's Theorem we have

\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48

As a result, the value of the double integral is -48-

3 0
3 years ago
Find the products<br> 6 + 8<br> 6 - 8
Oksanka [162]

Answer:

14

-2

Step-by-step explanation:

4 0
2 years ago
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What is scientific notation?
Montano1993 [528]
An expression to represent a decimal between 1 and 10 multiplied by ten. basically to write larger numbers with less digits.
 ex . 100 = 1 x 10^2
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7 0
3 years ago
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