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Travka [436]
3 years ago
12

Solve for X, please show work!

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0

Answer:

x < -2 or x > 10/3

Step-by-step explanation:

3x - 2 > 8

3x > 10

x > 10/3

-3x + 2 > 8

-3x > 6

x < -2

x < -2 or x > 10/3

Molodets [167]3 years ago
5 0

Answer:

the solution set consists of {x < -2 ∪ x > 10/3}

Step-by-step explanation:

|3x - 2| > 8 is equivalent to the following set of inequalities:

1) 3x - 2 > 8

and

2) -(3x - 2) > 8

In case 1, above, add 2 to both sides, obtaining 3x > 10, or x > 10/3.

In case 2, above, carry out the indicated multiplication first:

-3x + 2 > 8.  Next, subtract 2 from both sides:  -3x > 6.

Next, divide both sides by -3, remembering to reverse the direction of the inequality sign:  x < -2.

Thus, the solution set consists of {x < -2 ∪ x > 10/3}

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Look at the rectangle and the square:
OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0
2 years ago
Read 2 more answers
Herman and Helga had a combined gross income of $391,200 in 2009. When filing their federal income tax return with the Married F
viva [34]
33% depending on if your numbers is the same as mine

7 0
3 years ago
Read 2 more answers
Please help me thank you
Mashcka [7]

Answer:

f(2) 6x2= 12

f(-6) 6x-6=-36

f(5) 6x5=30

f(0) 6x0=0

f(10) 6x10=60

Step-by-step explanation:

it's really easy when they ask you this just put the number in parentheses instead of the x because x is an unknown number it's telling you to multiply the 6 by the number they give you

6 0
2 years ago
Find the value of the d. 2d - 5 = 17
LenKa [72]

Answer:

d = 11

Step-by-step explanation:

Isolate the variable (d). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, add 5 to both sides

2d - 5 (+5) = 17 (+5)

2d = 17 + 5

2d = 22

Next, divide 2 from both sides

(2d)/2 = (22)/2

d = 22/2

d = 11

11 is your answer for d.

~

6 0
2 years ago
What is a quick and easy way to remember explicit and recursive formulas?
Oliga [24]
I always found derivation to be helpful in remembering. Since this question is tagged as at the middle school level, I assume you've only learned about arithmetic and geometric sequences.

First, remember what these names mean. An arithmetic sequence is a sequence in which consecutive terms are increased by a fixed amount; in other words, it is an additive sequence. If a_n is the nth term in the sequence, then the next term a_{n+1} is a fixed constant (the common difference d) added to the previous term. As a recursive formula, that's

a_{n+1}=a_n+d

This is the part that's probably easier for you to remember. The explicit formula is easily derived from this definition. Since a_{n+1}=a_n+d, this means that a_n=a_{n-1}+d, so you plug this into the recursive formula and end up with 

a_{n+1}=(a_{n-1}+d)+d=a_{n-1}+2d

You can continue in this pattern, since every term in the sequence follows this rule:

a_{n+1}=a_{n-1}+2d
a_{n+1}=(a_{n-2}+d)+2d
a_{n+1}=a_{n-2}+3d
a_{n+1}=(a_{n-3}+d)+3d
a_{n+1}=a_{n-3}+4d

and so on. You start to notice a pattern: the subscript of the earlier term in the sequence (on the right side) and the coefficient of the common difference always add up to n+1. You have, for example, (n-2)+3=n+1 in the third equation above.

Continuing this pattern, you can write the formula in terms of a known number in the sequence, typically the first one a_1. In order for the pattern mentioned above to hold, you would end up with

a_{n+1}=a_1+nd

or, shifting the index by one so that the formula gives the nth term explicitly,

a_n=a_1+(n-1)d

Now, geometric sequences behave similarly, but instead of changing additively, the terms of the sequence are scaled or changed multiplicatively. In other words, there is some fixed common ratio r between terms that scales the next term in the sequence relative to the previous one. As a recursive formula,

a_{n+1}=ra_n

Well, since a_n is just the term after a_{n-1} scaled by r, you can write

a_{n+1}=r(ra_{n-1})=r^2a_{n-1}

Doing this again and again, you'll see a similar pattern emerge:

a_{n+1}=r^2a_{n-1}
a_{n+1}=r^2(ra_{n-2})
a_{n+1}=r^3a_{n-2}
a_{n+1}=r^3(ra_{n-3})
a_{n+1}=r^4a_{n-3}

and so on. Notice that the subscript and the exponent of the common ratio both add up to n+1. For instance, in the third equation, 3+(n-2)=n+1. Extrapolating from this, you can write the explicit rule in terms of the first number in the sequence:

a_{n+1}=r^na_1

or, to give the formula for a_n explicitly,

a_n=r^{n-1}a_1
6 0
3 years ago
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