Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:

The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.
X = 82:


Z = 1
Z = 1 has a p-value of 0.84.
X = 72:


Z = 0
Z = 0 has a p-value of 0.5.
0.84 - 0.5 = 0.34.
Out of 200 students, the number is given by:
0.34 x 200 = 68 students with scores between 72 and 82.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1
Answer:
Step-by-step explanation:
You can use Pythagoras Theorem,

∴
Hope that helps!!
Please mark as Brainliest!!
Answer:
A. -1/8 x + 3/16
Step-by-step explanation:
Distribute -1/2 over the parentheses
-1/2 ( 1/4 x - 3/8 )
-1/2 (1/4 x) - 1/2 (-3/8 )
multiply fractions to simplify
-1/8 x + 3/16
A is correct