3 years ago

8 customers entered a store over the course of 10 minutes.

Mathematics

1 answer:

katovenus [111]3 years ago

6 0

Answer:

what is the question?

Step-by-step explanation:

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xxTIMURxx [149]

Answer is C.

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4 0

3 years ago

What is the solution to the equation 3/m+3-m/3-m=m^2+9/m^2-9

Bas_tet [7]

Answer:

no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

$\dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}$

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

7 0

3 years ago

PLEASEEEE HELP MEEEEEEEEEE

umka21 [38]

Answer:
should be A. 5x+2

7 0

3 years ago

Find the value of x. Show all of your work!

Georgia [21]

Answer:

145⁰

Step-by-step explanation:

180 minus 73⁰ plus 62⁰

which is 180 minus 135

145⁰

7 0

3 years ago

Question 5 of 15

Licemer1 [7]

<h3>Isolate y on both equations then equate </h3>

x²-3x+2y=-4
2y=-x²+3x-4
y=-x²/2+3/2x-2

Now you can equate it with second one to get x

6 0

2 years ago

Read 2 more answers