Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Let C = cost to rent each chair
Let T = cost to rent each table
4C + 8T = 73
2C + 3T = 28
Multiply the 2nd equation by (-2) and then add the equations together
4C + 8T = 73
-4C - 6T = -56
2T = 17
T = 17/2 = 8.5
Plug this in to the 1st equation to solve for C
4C + 8(17/2) = 73
4C + 68 = 73
4C = 5
C = 5/4 = 1.25
So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50
Answer:
A = 8π cm²
Step-by-step explanation:
The area (A) of a circle is calculated as
A = πr² ( r is the radius )
Here diameter = 8 , then r = 8 ÷ 2 = 4
The area of half a circle is then
A =
π × 4² =
× π × 16 = 8π cm²
Answer:
Without any studying, the score would be about 328
Step-by-step explanation:
The y-intercept of an equation represents the point where its graph crosses the y-axis. At this point the value of x is always equal to 0.
The y-intercept of the equation in this context would represent the Math SAT score of a student who did not do any studying, that is the number of hours spent studying, x = 0.
Substitute x = 0 in the given equation and solve for y;
y = 24.387(0) + 328.182
y = 328.182
Therefore, Without any studying, the score would be about 328
Answer:
Step-by-step explanation:
Hello!
a)
- 11.5= a
b)
b= -11 -7 = -18
c)
c+3 = 15
c = 15 -3 = 12
d)
-4d = 32
d = -32/4 = -8