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Novosadov [1.4K]
3 years ago
9

-3t-8+7t =34 +9t -2 Solve for t Please give an exposition

Mathematics
2 answers:
notka56 [123]3 years ago
6 0

Answer: t= -8

Step-by-step explanation:

  • 3t-8+7t=34+9t-2
  • -3t+7t-8=9t+32-2
  • 4t-8=9t+32
  • t= -8
klasskru [66]3 years ago
4 0

Answer:

t = -8

Step-by-step explanation:

combine like terms, so -3t + 7t = 4t and 34 - 2 = 32

so 4t - 8 = 32 + 9t

then subtract 4t from both sides and subtract 32 from both sides. You will get: -40 = 5t.

Then divide both sides by 5 so you will get -8 = t

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| If f(x) = (3x – 1, find f(2) and f(-2)
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Answer:

f(2)=5, f(-2)=-7

Step-by-step explanation:

Step 1 : f(2)=3(x)-1

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Step-by-step explanation:

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2 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
Who is out of school tomorrow for the weather?<br>where do you live?​
ludmilkaskok [199]

Answer:

i sadly still have to go, i live in the east coast so the weather isn't bad

4 0
3 years ago
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