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4 years ago

What is the solution to the equation 3(x-4)=2(x-6)

Mathematics

2 answers:

Nataliya [291]4 years ago

8 0

Answer:

x=0

Step-by-step explanation:

3x-12=2x-12

3x=2x

3x-2x=-0

Rama09 [41]4 years ago

3 0

Answer:

Infinity, either way you do it you get infinity

Step-by-step explanation:

3 ( x -4 ) = 2 ( x - 6 )

Distribute 3 into ( x - 4 ) and distribute 2 into ( x - 6 )

3x - 12 = 2x - 12

Now since you can't have X on both sides you got to get rid of one, so minus 2x from both sides

( 3x - 2x ) - 12 = ( 2x - 2x ) - 12 ( the 2x cancels out on this side)

1x - 12 = - 12

Now add 12 to both sides ( if it were positive you would subtract it )

1x ( - 12 + 12 ) = ( -12 + 12 ) the 12 cancels out on both sides)

1x = 0 now divide the 1 to both sides

And you get INFINITY or - INFINITY

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3 years ago

What is the resulting equation when the expression for y in the second equation is substituted into the first equation? 3x y = 1

Natali5045456 [20]

After putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

GIven:

The equations are:

$3x + y = 1\\
y = 6 - 4x$

It is required to put the value of y from second equation to the first equation.

<h3>How to solve equations?</h3>

The value of y from the second equation is,

$
y = 6 - 4x$

Now, put this value of y in the first equation as,

$3x + y = 1\\
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2 years ago

Which of the sets of ordered pairs represents a function?

kodGreya [7K]

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Both A and B

Step-by-step explanation:

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3 years ago

Darla found that the least common denominator needed to subtract \frac{x}{x^2+4x-12}-\frac{3}{x+6}is (x + 6)(x – 2). Which is th

Leona [35]

<h3>Answer: Choice B</h3>

$\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}$

which is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

=====================================

Explanation:

The LCD is (x+6)(x-2) which is the factorization of x^2+4x-12, and that is the denominator of the first fraction. The first fraction has the LCD already. The second fraction does not. It has (x+6) but it is missing (x-2).

We multiply top and bottom of the second fraction by (x-2) to get the second fraction to have the LCD.

$\frac{3}{x+6}$ turns into $\frac{3}{x+6}*\frac{x-2}{x-2} = \frac{3(x-2)}{(x+6)(x-2)}$

------

So,

$\frac{x}{x^2+4x-12} - \frac{3}{x+6}$

$\frac{x}{(x+6)(x-2)} - \frac{3}{x+6}$

$\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}$

This is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

Note the parenthesis around "(x+6)(x-2)"

Instead of x/(x+6)(x-2) you should write x/( (x+6)(x-2) ) to ensure that all of "(x+6)(x-2)" is in the denominator.

4 0

3 years ago