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3 years ago

Find the slope of each line.

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

1.2

Step-by-step explanation:

Lets plug the points into the equation:

$\frac{((-1.5)-1.5)}{((-1.5)-1)} =\frac{-3}{-2.5} =1.2$

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The four swimmers listed in the table are trying out for the swim team. Two will make the team. How many different combinations

ratelena [41]

Number of possible combinations = (4x3) ÷ 2 = 6

Answer: There are 6 possible combinations.

8 0

3 years ago

Claudia's father is 7 times as old as Claudia. 20 years from now, Claudia will be 1/2 as old as her father. How old is Claudia's

Rudik [331]

I hope this helps you

Claudia x

father 7x

20 years later

x+20= 1/2 (7x+20)

2 (x+20)=7x+20

2x+40=7x+20

5x=20

x= 8

father 7.8=56

7 0

4 years ago

What is the value of X

bixtya [17]

All 3 angles have to add up to be 180 so the answer would be 90

5 0

3 years ago

Find an equation of the parabola with focus (2, −3) and directrix y = 1.

Likurg_2 [28]

Answer:

Step-by-step explanation:

The correct option is option (C).

The required equation of the parabola is

Step-by-step explanation:

Formula:

The distance of a point (x₁,y₁) from a line ax+by+c=0 is

The distance between two points (x₁,y₁) and (x₂,y₂) is

Given that, the focus of the parabola is (2,3) and directrix y= - 1.

We know that, a parabola is the locus of points that equidistant from the directrix and the focus.

Let any point on the parabola be P(x,y) .

The distance of P from the directrix is

=y+1

The distance of the point P from the focus (2,3) is

According to the problem,

The required equation of the parabola is

5 0

3 years ago

A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups

mash [69]

Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).

For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.

The sample mean is of 15, thus $\overline{x} = 15$ .
The sample standard deviation is of 9, thus $s = 9$ .
The sample size is of 10, thus $n = 10$ .

First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.

Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.

The margin of error is of:

$M = t\frac{s}{n}$

Then:

$M = 2.2622\frac{9}{\sqrt{10}} = 6$

The confidence interval is:

$\overline{x} \pm M$

Then

$\overline{x} - M = 15 - 6 = 9$

$\overline{x} + M = 15 + 6 = 21$

The confidence interval is (9, 21).

A similar problem is given at brainly.com/question/25157574

6 0

3 years ago