Question

3 QUESTIONS-30 POINTS ATTACHMENTS BELOW

Answer 1

(6) 70, 70, 110

∠2 = ∠4 = 110° ( congruent angles )

∠3 = 180° - 110° = 70° ( straight angle )

∠1 = 70° ( vertically opposite ∠3 )

(9) ∠AEC = 15x - 11

since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1

∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11

(7) x = 3

AC = AB + ABC = 32

2x + 6x + 8 = 32

8x + 8 = 32 ( subtract 8 from both sides )

8x = 24 ( divide both sides by 8 )

x = 3