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adoni [48]
3 years ago
15

A rectangle has base length

Mathematics
1 answer:
vekshin13 years ago
3 0
I believe that the answer is 22x
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Which of the following statements is not true?
Amiraneli [1.4K]

The above question is asking us to check if the exponents are written in the correct way or not.Let us look at the options one by one.

1) The exponent denotes the number of time the letter or number is multiplied.We have six x which are multiplied so the exponent for x which is 6 is right .The exponent is written correct .

2)We have seven A which are multiplied and five B multiplied making the exponent of A as 7 and B as 5 .The exponents are written correct.

3)There are six b and six c .The exponent rule has been followed here that is we can keep bc inside parenthesis and make 6 as the exponent.

4)Here exponent for x,y,z all are 5. we can not remove the exponent of x and y .It is not following the exponent rule .

Option 4 is not true.

4 0
2 years ago
Read 2 more answers
Find the range of the given data set.<br> -4, -3, -1, -1, 0, 1
Vika [28.1K]

Answer: 5

Step-by-step explanation:

Range = highest value - lowest value

The highest value from the data set given = 1

The lowest value = -4

Therefore :

Range = 1 - (-4)

Range = 1 + 4

Range = 5

3 0
2 years ago
Evaluate f(−1)=−3x^3 + 2x^2
Sholpan [36]

Answer:

5

Step-by-step explanation:

f(-1)= -3(-1)³+2(-1)²

= -3(-1)+2(1)

= 3+2

=5

5 0
2 years ago
Find the selling price of a $270 bicycle with a 24% markup.
lisov135 [29]
1 percent of $270 is 2.70 (you just move the decimal point). then multiply your 1 percent by 24 and you have the answer. I get $64.80, doing it on paper.
Add the 24 percent to the original price and you have your retail price: $334.80.  If you have a calculator, check my maths.
6 0
2 years ago
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Ted throws an object into the air with an initial vertical velocity of 54 feet per second from a platform that is 40 feet above
ANTONII [103]

PERFECT application of the general equation of things
that are moving up and down in gravity:

                               H(t) = H₀ + v₀t + 1/2 g t²

t  =  time after the toss
H(t)  =  height at any time after the toss
H₀  =  height from which it's tossed
v₀ =  initial speed
g  =  acceleration of gravity

I'm going to call 'UP' = the positive direction .
So ...

H₀ = +40 ft
v₀  =  +54 ft/sec
g  =  -32 ft/sec²

When the object hits the ground, H(t) = 0 .
So you have ...

   0  =  40  +  54 t  -  16 t²

Let me re-write that for you, to make it a
little easier and more familiar:

                                        - 16 t²  +  54 t  +  40  =  0       

Divide each side by -2 :      8 t²   -  27 t  -  20  =  0 

Now go to your toolbox, pull out your quadratic formula,
solve that quadratic equation, and you'll get the usual two
solutions. 

The positive one is the one you want. 

The negative one refers to time before the toss, and may be discarded.

4 0
3 years ago
Read 2 more answers
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