Identify the next three terms in the arithmetic sequence 4.2, 4.8, 5.4, 6.0,...

The sale tax in a certain state is 5 1/2%. What would be the tax on an item that costs $535.00

nexus9112 [7]

Answer:

$29.43

Step-by-step explanation:

5 1/2 % or 5.5% is 0.055 as a decimal. Multiply 535 by 0.055 to find what 5.5% of 535 is...

0.055(535) = 29.425

Since we're working with dollars, round to the nearest hundredth, which is

$29.43

7 0

4 years ago

Oliver read for 450 minutes this month. His goal is to read for 10% more minutes next month. If Oliver meet his goal, how many m

Digiron [165]

945 minutes.

10% of 450 is 45. 450 + 45 = 495. 450 + 495 = 945.

3 0

3 years ago

Read 2 more answers

Write a factor that you can use to rationalize the denominator of 4 6

RoseWind [281]

Answer:

2

Step-by-step explanation:

4/6, cancelling by 2

2/3

5 0

3 years ago

-3 = k/12 help please

lozanna [386]

Answer:

-36 = k

Step-by-step explanation:

-3 = k/12

Multiply each side by 12

-3*12 = k/12 *12

-36 = k

3 0

4 years ago

Read 2 more answers

Suppose that the neighboring cities of Tweed and Ledee are long-term rivals. Neal, who was born and raised in Tweed, is confiden

Makovka662 [10]

Complete Question

The option to the blank space are shown on the first uploaded image

Answer:

Neal's decision is to fail to reject the null hypothesis (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all Ledee household is greater than , 854.28 kWh

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 854.11$

The sample size is $n = 65$

The sample mean is $\= x = 879.28 \ kWh$

The standard deviation is $\sigma = 133.29 \ kWh$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o: \mu = 854.11$

The alternative hypothesis is $H_a : \mu > 854.11$

The t-statistics is $t = 1.522$

The p-value is $p-value = 0.066$

Now from the given data we can see that

$p-value < \alpha$

Generally when this is the case , we fail to reject the null hypothesis

So

Neal's decision is to fail to reject the null hypothesis (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all Ledee household is greater than , 854.28 kWh

8 0

3 years ago