Answer:
D. 18.68
Step-by-step explanation:

Applying PEMDAS as order of operations.
Solving the exponents first ![[(\frac{2}{5})^2=\frac{4}{25}]](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B2%7D%7B5%7D%29%5E2%3D%5Cfrac%7B4%7D%7B25%7D%5D)

Multiplying ![[53\times \frac{4}{25}=8.48]](https://tex.z-dn.net/?f=%5B53%5Ctimes%20%5Cfrac%7B4%7D%7B25%7D%3D8.48%5D)

Dividing ![[27\div \frac{5}{3}=16.2]](https://tex.z-dn.net/?f=%5B27%5Cdiv%20%5Cfrac%7B5%7D%7B3%7D%3D16.2%5D)

Adding and subtracting.

Answer:
Theanswer is 4/27.
Step-by-step explanation:
given that, F(x) = 4×(1/3)^x
now , F(3)= 4×(1/3)^3 ( putting value of x)
or, F(3) = 4×(1/27)
therefore, F(3)= 4/27... ans
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
3 4/5
Step-by-step explanation:
just add the whole number then add the numerator then the denominator stay the same
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Answer:she will have $25 left .
Step-by-step explanation:
0.25(60) = 15
$40 - $15 = $ 25